Simplify/Condense 1/2* log of x log of y log of z 1 2 ⋅ log(x) − log(y) log(z) 1 2 ⋅ log ( x) log ( y) log ( z) Simplify 1 2log(x) 1 2 log ( x) by moving 1 2 1 2 inside the logarithm log(x1 2) −log(y)log(z) log ( x 1 2) log ( y) log ( z) Use the quotient property of logarithms, logb (x)−logb(y) = logb( x y) log b ( xGet an answer for 'solve (yz)^log ylog z(zx)^log zlogx (xy)^log x logy solve (yz)^log ylog z(zx)^log zlogx (xy)^log x logy the dot represents multiplication sign ' and find homeworkSome more are there sigma r=1 to
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If log(x y/2)=1/2(logx logy) then find the value of x/y y/x- 57 views around the world You can reuse this answer Creative Commons License Ex 96, 7 For each of the differential equation given in Exercises 1 to 12, find the general solution 𝑥𝑙𝑜𝑔𝑥 𝑑𝑦/𝑑𝑥𝑦=2/𝑥 𝑙𝑜𝑔𝑥 Step 1 Put in form 𝑑𝑦/𝑑𝑥 Py = Q xlog x 𝑑𝑦/𝑑𝑥 y = 2/𝑥 log x Dividing by x log x, 𝑑𝑦/𝑑𝑥𝑦" × " 1/(𝑥 log𝑥 ) = 2/𝑥 𝑙𝑜𝑔 𝑥" × " 1/(𝑥 log𝑥 ) 𝑑𝑦
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Log (ex 2) 18 logx y = Tan1 1 – 2 logx Tan1 4 2 log x 1 2 log x 1 – 4 (2 logx ) Y= Tan1 1Tan1 (2logx ) Tan1 4 Tan1 (2logx ) diff wrt 'x' dy/dx = 0 d2y = 0 AnswerIf a 2 and b 1 then what is the value of log a b if log 2 the value of log 80 if log102 = , what is the number of digits in 2^64 if log2= the number of digits in 5^ log 10 7Graph y = log of x2 y = log(x 2) y = log ( x 2) Find the asymptotes Tap for more steps Set the argument of the logarithm equal to zero x 2 = 0 x 2 = 0 Subtract 2 2 from both sides of the equation x = − 2 x = 2 The vertical asymptote occurs at x = − 2 x = 2
The equation 2 lo g 2 (lo g 2 x) lo g 1 / 2 lo g 2 (2 2 x ) = 1 has View solution If lo g 2 = 0 3 0 1 0 and lo g 3 = 0 4 7 7 1 , then the value of lo g 2 4 will beLog{{xy}/3}=1/2{logxlog Y} log(xy) log(3) = 1/2(log xy) log(xy) log(2) = 1/2(log xy) 2xy 4 = xy xy = 4 now x/y y logx^(1/2)/(y^5z) Use the power law first logx^(1/2) logy^5 logz If the logs are being subtracted, then the values were being divided Write as a log of a single term logx^(1/2)/(y^5z)
logx logy = 6 logx logy = 2 Now just solve as usual for logx and logy Then raise whatever base you are using (probably 10) to the respective powers 👍 The point of intersection is (10, 1/10), assuming the logarithms are in base 10 Isolate the logx in equation 1 logx = 2 logy Substitute for logx in equation 2 2 logy logy = 0 2 2logy = 0 2(1 logy) = 0 logy = 1 y = 10^1 y = 1/10 logx = 2 log(1/10) logx log(1/10) = 2 log(x/(1/10)) = 2 10x = 10^2 10x = 100 x = 10 The solution point is (10, 1/10) Hopefully this helps!X 1 , x 2 , x n and y 1 , y 2 , y n form an ascending arithmetic progression with common difference 2 and 4 respectively, then the coordinates of G in Q 1 are Medium View solution
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Related Searches to log xY = 100 and log x2 = 10, then the value of y is ?0 We can write the term of interest as log ( 1 x 2) = log ( 1 y 2) = ∫ y x 2 t 1 t 2 d t Now, the integrand f ( t) = 2 t 1 t 2 attains its maximum value of 1 when t = 1 Therefore, the inequality follows immediately from the mean value theorem 2 Answers2 This is because x = y = 1 is the only solution to the given equation Note that the minimum value of x log (x) is 1 and that happens when x = 1 Obviously, the same is true for y log (y) So, log (x)log (y)xy is always greater than 2 except at x = y = 1, where it is exactly equal to 2
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Get answer If x^2y^2=27xy, then show that log((xy),(5))=1,2logxlogyIf i assumed a value 1 for y then i was able to solve for x to get x = and x = i confirmed that when x = 685 and y = 1, the original equation is true log (sqrt4(x^16 / y^4)) What is the value of the expression when logx=8 and logy=1?
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x/y =1/2(3 sqrt(5)) From 2 log(xy)=log x log y we know (xy)^2=xy Now calling x = lambda y and substituting (lambda yy)^2=lambda y^2 or supposing y > 0 (lambda1)^2=lambda Solving for lambda lambda^23lambda1 = 0 lambda = 1/2(3 pm sqrt(5)) so remembering that x > y the feasible solution is x/y =1/2(3 sqrt(5)) log (xy)/2 = 1/2 ( logx logy) log (xy) / 2 = 1/2logxy xy/2 = √xy xy = 2√xy Squaring on both sides;Rewrite in Exponential Form log of x=1/2 log(x) = 1 2 log ( x) = 1 2 For logarithmic equations, logb(x) = y log b ( x) = y is equivalent to by = x b y = x such that x > 0 x > 0, b > 0 b > 0, and b ≠ 1 b ≠ 1 In this case, b = 10 b = 10, x = x x = x, and y = 1 2 y = 1 2 b = 10 b = 10 x = x x = x
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$\log{\Big(\dfrac{xy}{3}\Big)}$ $\,=\,$ $\dfrac{1}{2}(\log{x}\log{y})$ The left hand side expression is purely in logarithmic form but the right hand side expression is also in logarithmic form but the factor $\dfrac{1}{2}$ pulled us back in eliminating the logarithmic form from the equation10th class mathematics Mathematics, ncert, SSC, telangana board mathematics, andhra board mathematics, state syllabus, real numbers, logarithms, sets, polynYou can put this solution on YOUR website!
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My work x=10^8 y=10 I tried to plug these in but my calculator but it said "overflow" Is there an easier way to do this?Click here👆to get an answer to your question ️ If log ( x y3 ) = 12 (logx logy) , then find the value of xy yxCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history
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